-16t^2+70t=5.9

Solution for -16t^2+70t=5.9 equation:

-16t^2+70t=5.9

We move all terms to the left:

-16t^2+70t-(5.9)=0

We add all the numbers together, and all the variables

-16t^2+70t-5.9=0

a = -16; b = 70; c = -5.9;
Δ = b2-4ac
Δ = 702-4·(-16)·(-5.9)
Δ = 4522.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-\sqrt{4522.4}}{2*-16}=\frac{-70-\sqrt{4522.4}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+\sqrt{4522.4}}{2*-16}=\frac{-70+\sqrt{4522.4}}{-32}
$